1.

Find the zeroes of x²-x-12 *

Answer»

x²-x-12

x²-(4-3)x-12=0

x²-4x+3x-12=0

x(x-4) +3(x-4) =0

(x-4) (x+3)=0

:.x-4=0 or , x+3=0

x=4 x=-3

gm❤



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