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Find the zeroes of x2_2x_8and verify the selationshi p |
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Answer» given, x²-2x-8=0 x²+2x-4x-8=0 x(x+2)-4(x+2)=0 (x+2)(x-4)=0 x= 4, -2 PLZ MARK ME THE BRAINLIEST!!! |
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