1.

Find the zeroes of x²-2x

Answer»

ANSWER:

\mathfrak{Quadratic\:Formula:}

\bf{\frac{-b \pm \sqrt{b^{2} - 4ac}}{2a}}\\

=》 a = 1, b = (-2), C = 0

=》 \bf{\frac{2 \pm \sqrt{2^{2} - 4(1)(0)}}{2(1)}}\\

=》 \bf{\frac{2 \pm \sqrt{4}}{2}}\\

=》 \bf{\frac{2 \pm 2}{2}}\\

=》 x = 0, 2

Therefore, zeroes = 0 and 2


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