1.

Find the zeroes of X2 +13x+1​

Answer»

\blue{\bold{\underline{\underline{Answer:}}}}

\green{\tt{\therefore{Value\:of\:x=\frac{-13\pm\sqrt{165}}{2}}}}\\

\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}

\green{\underline \bold{<klux>GIVEN</klux> :}} \\ \tt:\implies {x}^{2} + 13x + 1 = 0 \\ \\ \red{\underline \bold{To \: Find :}} \\ \tt:\implies Zeroes =?

• ACCORDING to given QUESTION :

\tt \circ \: a = 1 \: \: \: \: \: \: b = 13 \: \: \: \: \: \: c = 1 \\ \\ \bold{As \: we \: know \: that} \\ \tt: \implies D= {b}^{2} - 4ac \\ \\ \tt: \implies D= {13}^{2} - 4 \times 1 \times 1 \\ \\ \tt: \implies D = 169 - 4 \\ \\ \green{\tt: \implies D = 165} \\ \\ \bold{As \: we \: know \: that} \\ \tt: \implies x = \frac{ - b \pm \sqrt{D} }{2a} \\ \\ \tt: \implies x = \frac{ - 13 \pm \sqrt{165} }{2 \times 1} \\ \\ \green{\tt: \implies x = \frac{ - 13 \pm \sqrt{165} }{2} }


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