1.

find the zeroes of the quadratic polynomials 8x²-3x and verify the relationship between the zeroes and the coefficients.​

Answer»

Step-by-step explanation:

LET F(x)=8x

2

−4

= 4((

2

x)

2

−(1)

2

)

=4(

2

x+1)(

2

x−1)

to find the zeroes, Let f(x)=0

(

2

x+1)(

2

x−1)=0

(√2x+1)=0 or (√2x−1)=0

x=

2

(−1)

or x=

2

1

So the zeroes of f(x) are

2

−1

and x=

2

1

Again

Sum of zeroes =

2

−1

+

2

1

=

2

(−1+1)

=0=

a

−b

=

(coefficient of x

2

)

(−coefficient of x)

Product of zeroes =

2

−1

×

2

1

=

2

−1

=

8

−4

=

a

c

=

coefficient of x

2

CONSTANT TERM


Discussion

No Comment Found

Related InterviewSolutions