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Find the zeroes of the quadratic polynomial by splitting middle term of x² + 5x + 6 |
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Answer» x²+5x+6=0or, x²+3x+2x+6=0or, x(x+3)+2(x+3)=0or, (x+3)(x+2)=0or, roots are, x+3=0 x= -3 And x-2=0 x=2 ? @ns... X² +5x+6X²+(6-1)x+6X²+6x-1x+6X(x+6)-1(x+6)X+6=0 & X-1=0X=-6 & X= 1 |
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