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find the zeroes of the quadratic polynomial 3x^2 - x - 4 and verify the relationship between the zeroes and the coefficient . answers bta jaldi |
Answer» ANSWER:-1 and 4/3 are the zeroes of the given polynomial. Step-by-step explanation:Given polynomial, 3x² - x - 4 x² coefficeint = 3 x COEFFICIENT = -1 constant term = -4
3x² - x - 4 = 0 3x² + 3x - 4x - 4 = 0 3x(x + 1) - 4(x + 1) = 0 (x + 1) (3x - 4) = 0
=> x + 1 = 0 x = -1 => 3x - 4 = 0 x = 4/3 -1 and 4/3 are the zeroes of the given polynomial.
we know, Sum of zeroes = -(x coefficient)/x² coefficient PRODUCT of zeroes = constant term/x² coefficient ⇒ Sum of zeroes = -1 + 4/3 = (-3+4)/3 = 1/3 = -(-1)/3 = -(x coefficient)/x² coefficient ⇒ Product of zeroes = (-1) (4/3) = -4/3 = constant term/x² coefficient Hence verified! |
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