1.

Find the zeroes of the polynomials p(x​

Answer»

Step-by-step EXPLANATION:

\:  \:  \:  \: 2 {x}^{2}  + 5x - 12 = <klux>0</klux> \\  =  > 2 {x}^{2}   +  8x - 3x - 12 = 0 \\  =  > 2x(x + <klux>4</klux>) - 3(x + 4) = 0 \\  =  > (x + 4)(2x - 3) = 0

x+4=0. |. 2x-3. =0

=>. x=-4. |. => 2x=3

|. =>. x=3/2

x=. -4 and 3/2.



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