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Find the zeroes of the polynomials mx^2+(m+n)x+n |
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Answer» Step-by-step explanation: mx^2+(m+N)x+n Solving by SPLITTING the MIDDLE term METHOD, mx^2+mx+nx+n Taking mx common , mx(x+1)+nx+n Taking n common, mx(x+1)+n(x+1) Zeroes= mx+n=0 x=-n/m Also, x+1=0 x=-1 |
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