1.

Find the zeroes of the polynomial and and verify the relationship between the zeroes and coefficient .x2-x-90 ​

Answer»

Answer:-

Given POLYNOMIAL : x² - X - 90

By splitting the MIDDLE term,

→ x² - 10x + 9x - 90 = 0

→ x (x - 10) + 9(x - 10) = 0

→ (x + 9) ( x - 10) = 0

→ x + 9 = 0

→ x = - 9

(or)

→ x - 10 = 0

→ x = 10

Verification:

LET a = 1 , b = - 1 , c = - 90

Sum of the zeroes = - b/a

→ 10 + ( - 9) = - ( - 1) / 1

→ 10 - 9 = 1/1

→ 1 = 1

Product of the zeroes = c/a

→ (10) * ( - 9) = - 90/1

→ - 90 = - 90

Hence, Verified.


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