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Find the zeroes of the polynomial 7n2 + 3(3n) - 1. |
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Answer» 7n2+ 9x - 1 n = \(\frac{-9\pm\sqrt{81+28}}{14}=\frac{-9\pm{109}}{14}\) Zeros are \(\frac{-9+\sqrt{109}}{14}\) & \(\frac{-9-\sqrt{109}}{14}\) |
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