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Find the zeroes of the polynomial |
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Answer» Answer: Z^2 - 8= z^2 - (2√2)^2Using a^2 - b^2 = (a+b) (a-b) z^2 - (2√2)^2 = 0=> (z - 2√2) (z + 2√2) = 0Therefore, (z - 2√2) = 0 OR(z + 2√2) = 0So, z = 2√2 or (-2√2).✨✨Hope it will HELP you.✨✨ |
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