Find the zeroes of the following quadratic polynomial 4u^2+8u

1.	Find the zeroes of the following quadratic polynomial 4u^2+8u
Answer» 4u^2+8u=4u(u+2)Either 4u=0 =u=0/4=0Or u+2=0 =u=-2 Zeros are 0,-2Sum of zeros=o+(-2)=-2=-8/4=-(Coefficient of u)/(Coefficient of u^2)Product of zeros=0×(-2)=0=0/4=constant term/Coefficient of u^2 4u

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