Find the zeroes of the following quadratic equation

1.	Find the zeroes of the following quadratic equation
Answer» QUESTION : find the zeroes of the QUADRATIC equation x² - 2X - 8 GIVEN : $\tt \implies {x}^{2} - 2x - 8$ To Find : Zeroes of the quadratic equation Solution : Quadratic formula $\large \boxed{ \tt x = \frac{ - b \pm \sqrt{ {b}^{2} - 4ac } }{2a} } \\ \\ \tt \implies {x}^{2} - 2x - 8 \\ \\ \tt here \\ \\ \tt \boxed{ \tt a = 1} \: \: \: \boxed{ \tt b = - 2 } \: \: \: \boxed{ \tt c = - 8} \\ \\ \tt Put \: values \: in \: the \: formula \\ \\ \tt x = \frac{ - ( - 2) \pm \sqrt{ { (- 2)}^{2} - 4 \times 1 \times ( - 8) } }{2 \times 1} \\ \\ \tt x = \frac{2 \pm \sqrt{4 + 32} }{2} \\ \\ \tt x = \frac{2 \pm \sqrt{36} }{2} \\ \\ \tt x = \frac{2 \pm 6}{2} \\ \\ \tt \bullet \: x = \frac{2 + 6}{2} \\ \\ \large\boxed{ \tt x = 4} \\ \\ \tt \bullet \: x = \frac{2 - 6}{2} \\ \\\large \boxed{ \tt x = - 2}$ $\large \underline{\tt Zeroes \: of \: equation \: are \: 1 \: and \: - 2}$

Answer»

QUESTION :

find the zeroes of the QUADRATIC equation x² - 2X - 8

To Find :

Zeroes of the quadratic equation

Solution :

Quadratic formula

$\large \boxed{ \tt x = \frac{ - b \pm \sqrt{ {b}^{2} - 4ac } }{2a} } \\ \\ \tt \implies {x}^{2} - 2x - 8 \\ \\ \tt here \\ \\ \tt \boxed{ \tt a = 1} \: \: \: \boxed{ \tt b = - 2 } \: \: \: \boxed{ \tt c = - 8} \\ \\ \tt Put \: values \: in \: the \: formula \\ \\ \tt x = \frac{ - ( - 2) \pm \sqrt{ { (- 2)}^{2} - 4 \times 1 \times ( - 8) } }{2 \times 1} \\ \\ \tt x = \frac{2 \pm \sqrt{4 + 32} }{2} \\ \\ \tt x = \frac{2 \pm \sqrt{36} }{2} \\ \\ \tt x = \frac{2 \pm 6}{2} \\ \\ \tt \bullet \: x = \frac{2 + 6}{2} \\ \\ \large\boxed{ \tt x = 4} \\ \\ \tt \bullet \: x = \frac{2 - 6}{2} \\ \\\large \boxed{ \tt x = - 2}$