1.

find the zeroes of p(x) =√2xsquare+7x+5√2 and verify the relationship between zeroes and coefficient​

Answer»

ANSWER:

√2x^2+7x+5√2 =0\\√2x^2+7x+5√2=0\\√2x^2+5x+2x+5√2=0\\x(√2x+5)+√2(√2x+5)=0\\(√2x+5)(x+√2)=0\\x= \frac {-5}{√2}, {-√2}

FIND the RELATIONSHIP by own..XD



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