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Find the zeroes of 7y^2-11/3y-2/3 and also find the relationship between the zeroes of the polynomial and their coefficient...Hey guys plz solve this question seriously...For a brainliest batch!!Thank you

Answer»

The GENERAL form of quadratic EQUATION is
ax² + b x+ c = 0


7y²-11/3y-2/3 = 0
21y²-11y-2 = 0
21y²-14y+3y-2=0
7y(3y-2)+1(3y-2) = 0
(7y+1)(3y-2)=0
y=-1/7 and 2/3

sum of ZEROES = -1/7 + 2/3
= -3+14/21
= 11/21
= -b/a

product of zeros = (-1/7)(2/3)
= -2/21
= c/a

here is UR answer

i hope it helps u



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