1.

Find the zero of the polynomial p(x)=x2-16​

Answer»

<P>Given -

  • p(x) = x² - 16

To Find -

  • Zeroes of the polynomial

Now,

→ x² - 16

→ (x)² - (4)²

  • Using the identity of a² - b² = (a + b)(a - b)

→ (x + 4)(x - 4)

Zeroes are -

→ x + 4 = 0 and x - 4 = 0

→ x = -4 and x = 4

Verification :-

  • α + β = -b/a

→ -4 + 4 = -(0)/1

→ 0 = 0

LHS = RHS

And

  • αβ = c/a

→ -4 × 4 = -16/1

→ -16 = -16

LHS = RHS

Hence,

Verified...

It SHOWS that our answer is ABSOLUTELY CORRECT.


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