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Find the work required to make a soap bubble of radius 0.02m?Surface Tension of soap solution=0.03N/m. |
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Answer» of the soap bubble= 0.02 m ∛ ⇒Surface tension of the soap solution=0.03N/m ⇒Let us find the surface AREA. so , ⇒surface area = 4(π) r² .⇒=4×22/7×(0.2 )² ⇒No .of surface area of the soap bubble = 2 ( OUTER and inner area ) ⇒Surface area is GIVEN as TΔS per surface ⇒Let us NEXT find the total surface area =2 (TΔS) ⇒E = 2 ×0.03 × 4×22/7 × (0.2 )² Joule.....is the ans. |
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