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Find the wavelength of second line of lyman series in li 2+ Ion spectrum?

Answer» R VALUE is constant= 1.08×10power7metreinverse1/wave length=R[1/n1square_1/n2 square]n1=1,n2= 31/wave length=1.08×10power7 ×8÷9wave length =10.4×10power_8cmExplanation:please MARK me as BRANLIEST


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