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Find the volume of Co2 obtained at STP by heating 50 grams of caco3?( atomic mass of CA is 40 C is 12 16) |
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Answer» The answer is 11.2 L Explanation: on heating CaCO₃ 1 MOLE of CaCO₃ GIVES 1 mole of CO₂ at STP 1 mole = 22.4 L given : 50 grams of CaCO₃ is heated . which is equal to 0.5 mole. so , 0.5 mole of CaCO₃ gives 0.5 mole of CO₂. 0.5 moles = 11.2 L ( at STP ) |
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