1.

Find the volume of Co2 obtained at STP by heating 50 grams of caco3?( atomic mass of CA is 40 C is 12 16)

Answer»

ANSWER:

The answer is 11.2 L

Explanation:

on heating CaCO₃

CaCO_3 --> CaO + CO_2

1 MOLE of CaCO₃ GIVES 1 mole of CO₂

at STP 1 mole = 22.4 L

given :

50 grams of CaCO₃ is heated .

which is equal to  0.5 mole.

so , 0.5 mole of CaCO₃ gives 0.5 mole of CO₂.

0.5 moles = 11.2 L ( at STP )



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