Find the vertex of the quadratic function: f(x)=x^2+10x+14The equation

1.	Find the vertex of the quadratic function: f(x)=x^2+10x+14The equation for the vertex is:X=-b/2ay=f(-b/2a)Pre-calc Answer!
Answer» ANSWER: ( - 5, - 11) Step-by-step explanation: f(X) = x² + 10x + 14 The coordinates for the vertex are: y = f( - 5) =( - 5)² + 10 × ( - 5) + 14 = - 11 ( - 5, - 11) Zeroes of given FUNCTION are = - 5 ± √11

Find the vertex of the quadratic function: f(x)=x^2+10x+14The equation for the vertex is:X=-b/2ay=f(-b/2a)Pre-calc Answer!

Answer»

ANSWER:

( - 5, - 11)

Step-by-step explanation:

f(X) = x² + 10x + 14

The coordinates for the vertex are:

y = f( - 5) =( - 5)² + 10 × ( - 5) + 14 = - 11

( - 5, - 11)

Zeroes of given FUNCTION are = - 5 ± √11

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Find the vertex of the quadratic function: f(x)=x^2+10x+14The equation for the vertex is:X=-b/2ay=f(-b/2a)Pre-calc Answer!

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