Find the vector of magnitude 11 units in the direction opposite to pqw

1.	Find the vector of magnitude 11 units in the direction opposite to pqwhere p(1 3 2) and q(-1 0 8)
Answer» <P>The vector with INITIAL POINT P(1,3,2) And TERMINAL point Q(-1,0,8) is given by PQ = (-1-1)i + (0-3)j + (8-2)k PQ = - 2i - 3j + 6K QP = -PQ = - 1(- 2i - 3j + 6k) QP vector = 2i +3j - 6k IQPI = $\sqrt{(2^2) + (3^2) + (-6^2)}$ IQPI = $\sqrt{49}$ = 7 Therefore unit vector in direction of QP vector is given by QP unit vector = QP vector/IQPI QP unit vector = (2i +3j - 6k)/7 QP unit vector = (2/7) i + (3/7) j - (6/7) k Hope my answer and picture attached will satisfy you.

Find the vector of magnitude 11 units in the direction opposite to pqwhere p(1 3 2) and q(-1 0 8)

Answer»

<P>The vector with INITIAL POINT P(1,3,2) And TERMINAL point Q(-1,0,8) is given by

PQ = (-1-1)i + (0-3)j + (8-2)k

PQ = - 2i - 3j + 6K

QP = -PQ = - 1(- 2i - 3j + 6k)

QP vector = 2i +3j - 6k

IQPI = $\sqrt{(2^2) + (3^2) + (-6^2)}$

IQPI = $\sqrt{49}$ = 7

Therefore unit vector in direction of QP vector is given by

QP unit vector = QP vector/IQPI

QP unit vector = (2i +3j - 6k)/7

QP unit vector = (2/7) i + (3/7) j - (6/7) k

Hope my answer and picture attached will satisfy you.

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Find the vector of magnitude 11 units in the direction opposite to pqwhere p(1 3 2) and q(-1 0 8)

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