1.

Find the vector equation of the plane passing thrugh a point having position vector `3hati-3hatj+hatk` and perpendicular to the vector `4hati+3hatj+2hatk.`

Answer» We know that the vector equation of the plane passing through a point `A(veca)` and normal to `vecn` is `vecr*vecn=veca*vecn.`
Here, `veca=3hati-3hatj+hatkand vecn=4hati+3hatj+2hatk.`
`therefore` The equation of the required plane is
`vecr*(4hati+3hatj+2hatk)=(3hati-2hatj+hatk)(4hati+3hatj+2hatk)`
`vecr*(4hati+3hatj+2hatk)=12-6+2`
`vecr*(4hati+3hatj+2hatk)=8`
This is the required vector equation.


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