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Find the vector equation of the plane passing thrugh a point having position vector `3hati-3hatj+hatk` and perpendicular to the vector `4hati+3hatj+2hatk.` |
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Answer» We know that the vector equation of the plane passing through a point `A(veca)` and normal to `vecn` is `vecr*vecn=veca*vecn.` Here, `veca=3hati-3hatj+hatkand vecn=4hati+3hatj+2hatk.` `therefore` The equation of the required plane is `vecr*(4hati+3hatj+2hatk)=(3hati-2hatj+hatk)(4hati+3hatj+2hatk)` `vecr*(4hati+3hatj+2hatk)=12-6+2` `vecr*(4hati+3hatj+2hatk)=8` This is the required vector equation. |
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