1.

Find the valus of k2x2 + kx + 3 = 0 ​

Answer»

QUESTION:

Find the values of k so that the POLYNOMIAL has two EQUAL roots.

2x^{2} + kx + <klux>3</klux> = 0

Solution:

In the given polynomial,

a = 2

b = k

c = 3

Roots are equal here,

\boxed{ D = b^{2} - 4ac = 0}

b^{2} - 4ac = 0 \\ k^{2} - 4(2)(3) = 0 \\ k^{2} = 24 \\ k = \pm\sqrt{24}

Therefore, the values of k are -\sqrt{24} and +\sqrt{24}


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