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Find the values of `k`for which the points `(2k ,3k),(1,0),(0,1),a n d(0,0)`lie on a circle. |
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Answer» Correct Answer - `5//13` The circle passing through (1,0),(0,1) and (0,0) is `x(x-1)+y(y-1)=0` It also passes through the point (2k,3k). Therefore, `2k(2k-1)+3k(3k-1)=0` i.e., `k=0` or `k=(5)/(13)` |
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