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Find the values of k for the following quadratic equation, so that they have two eua(r-2) +6 0k2kx +6o.rootskrP.S.E.B. 2017 Sel-A

Answer»

kx(x-2) + 6 = 0kx^2 - 2kx + 6 = 0for equal rootsD=0b^2 -4ac=04k^2 -24k=04k(k-6)=0k=0,6



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