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Find the values of k for equation has real and distinct roots.kx2 + 6x + 1 = 0 |
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Answer» Given, kx2 + 6x + 1 = 0 It’s of the form of ax2 + bx + c = 0 Where, a =k, b = 6, c = 1 For the given quadratic equation to have real roots D = b2 – 4ac > 0 D = (6)2 – 4(1)(k) > 0 ⇒ 36 – 4k > 0 ⇒ 4k < 36 ⇒ k < 9 The value of k should be lesser than 9 to have real and distinct roots. |
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