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Find the values of a and b so that thhe polynomial x^3- ax^2-13x+b has x-1 and x-3 as factorsshow full calculations ill mark as brainliest |
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Answer» polynomial , x³ -ax² -13x + B has two factors ( x -1) and (x +3) it means , x = 1 and -3 are the roots (zeros ) of x³ -ax² -13x + b . so, put x = 1 in polynomial ,. (1)³ -a(1)² -13(1) + b = 0 1 - a -13 + b = 0 -a + b = 12 ---------(1) put x = -3 (-3)³ -a(-3)² -13(-3) + b = 0 -27 -9a +39 + b = 0 -9a + b = -12 --------(2) subtract equation (1) and (2) -a + b + 9a - b = 12 + 12 8a = 24 a = 3 put a = 3 in equation (1) b = 15 HOPE IT HELPS YOU......................... MARK IT BRAINLIEST... |
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