1.

Find the values of 6C3 and 30C28.

Answer»

(i) 6C3 = \(\frac{6\times5\times4}{1\times2\times3}\) = 20

(ii) 30C28 = 30C28 - 20 30C\(\frac{30\times29}{1\times2}\) = 435.



Discussion

No Comment Found