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Find the values of 6C3 and 30C28. |
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Answer» (i) 6C3 = \(\frac{6\times5\times4}{1\times2\times3}\) = 20 (ii) 30C28 = 30C28 - 20 = 30C2 = \(\frac{30\times29}{1\times2}\) = 435. |
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