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Find the valueo of a in the following: 6/3√2-2√3=3√2-a√3 |
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Answer» Answer: ❍ Let Gaurav's and Sachin's ages one year ago be 6x and 7x respectively. Then, — Four years hence their ages; Gaurav's AGE = (6x + 1) + 4 = (6x + 5) years Sachin's age = (7x + 1) + 4 = (7x + 5) years \underline{\bigstar\:\boldsymbol{ACCORDING\; to \;the\; given\; Question :}} ★AccordingtothegivenQuestion:
⠀ According to given CONDITION, Four years hence the ratio of their ages (Gaurav's age & Sachin's age) would become 7: 8. ⠀ Therefore, ⠀ \begin{gathered}:\implies\sf \dfrac{(6x + 5)}{(7x + 5)} = \dfrac{7}{8} \\\\\\:\implies\sf 8(6x + 5) = 7(7x + 5) \\\\\\:\implies\sf 48x + 40 = 49x + 35\\\\\\:\implies\sf 48x - 49x = 35 - 40 \\\\\\:\implies\sf \cancel{\;-}\:1x = \cancel{\;-}\;5\\\\\\:\implies{\underline{\boxed{\frak{\pink{x = 5}}}}}\;\bigstar\end{gathered} :⟹ (7x+5) (6x+5)
= 8 7
:⟹8(6x+5)=7(7x+5) :⟹48x+40=49x+35 :⟹48x−49x=35−40 :⟹ −
1x= −
5 :⟹ x=5
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⠀ Hence, ⠀ Gaurav's present age = (6x + 1) = 6(5) + 1 = (30 + 1) = 31 years. Sachin's present age = (7x + 1) = 7(5) + 1 = (35 + 1) = 36 years. ⠀ \therefore{\underline{\textsf{Hence, \; Sachin\;is\;\textbf{36 years}\;OLD.}}}∴ Hence, Sachinis36 yearsold.
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