Find the value of x¹/² y-¹ and z²/³ when x=9,y=3 and z=8

1.	Find the value of x¹/² y-¹ and z²/³ when x=9,y=3 and z=8
Answer» ANSWER: Step-by-step explanation: ANSWER Given equations are x² + y² + z² = 525 xy + yz + zx = 50 Per algebraic identity. (X + y + z )² = x² + y² + z² + 2XY + 2yz + 2zx (x + y + z )² = x² + y² + z² + 2(xy+yz+zx) = 525+2(50) = 625 x+y+z = √625 = ±25 After squareroot will be cancelled , the number BECOME ±25. ( x + y + z )² = x² + y² + z² + 2xy +2yz +2zx ( ±25 )² = 525 + 2( 50 ) 625 = 525 + 100 625 = 625 L.H.S = R.H.S. So , the answer is ' ±25 '.

Answer»

ANSWER:

Step-by-step explanation:

ANSWER

Given equations are x² + y² + z² = 525

xy + yz + zx = 50

Per algebraic identity.

(X + y + z )² = x² + y² + z² + 2XY + 2yz + 2zx

(x + y + z )² = x² + y² + z² + 2(xy+yz+zx)

= 525+2(50)

= 625

x+y+z = √625

= ±25

After squareroot will be cancelled , the number BECOME ±25.

( x + y + z )² = x² + y² + z² + 2xy +2yz +2zx

( ±25 )² = 525 + 2( 50 )

625 = 525 + 100

625 = 625

L.H.S = R.H.S.

So , the answer is ' ±25 '.

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Find the value of x¹/² y-¹ and z²/³ when x=9,y=3 and z=8​

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Find the value of x¹/² y-¹ and z²/³ when x=9,y=3 and z=8