1.

Find the value of x such that:♤ see attachment​

Answer»

ANSWER:

GYAN PRAKASH VERMA

Step-by-step EXPLANATION:

( \frac{p}{q} )^{3x+ 2} = ( \frac{q}{p}) ^{2 - x}

= ( \frac{q}{p}) ^{2 - x} \times \frac{q}{p}^{3x + 2}

so \\ according \: to \: law \: = {a}^{t} \times {a}^{u} = {a}^{t} \times ^{u}

= (\frac{q}{p} ) ^{2 - x} + ^{3x + 2}

3x + 2 = 2 - x \\ 3x + x = 2 - 2 \\ 4x = 0 \\ x = 0


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