1.

Find the value of x in : |x+3|-|x|=3 ​

Answer»

ong>Answer:

Let mod (x-2) = A & mod ( x-3) = B, both A& B are positive.

And since A + B = 1

So A & B can hold values from 0 to 1

ie 0 < ,= A <,=1

Also, 0 < , = B < , = 1

=> 0 < mod (x - 2) < 1 ……………..(1)

And 0 < mod ( x-3) < 1 ……………(2)

=> x-2 = 0 through 1 ( by (1)

=> x = 2 through 3 ●●●●●●●(3)

Now, x-3 = 0 through 1

=> x = 3 through 4 ●●●●●●●●(4)

Now we select the values of x from ●●●(3) & ●●●(4) , which satisfy EQUATIONS …(1) & ….(2) both

And those are

x = 2 through 3

ie, 2 <,= x <,= 3

So, values of x are all real numbers LYING between 2 & 3 , INCLUDING 2 & 3.

Step-by-step explanation:


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