Find the value of x in the equation sin2x = sin 45° cos 45°+ sin 30�

1.	Find the value of x in the equation sin2x = sin 45° cos 45°+ sin 30°→Note:- Please don't give any unnecessary answer as well as wrong answer I request to all... and by the way it's a question of class 10's sample papers.
Answer» ANSWER: x=45 Step-by-step EXPLANATION: SIN2X= sin45cos45+sin30 sin2x= 1/√2×1/√2+1/2 sin2x=1/2+1/2 sin2x=1 sin2x=sin90 2x=90 x=45

Find the value of x in the equation sin2x = sin 45° cos 45°+ sin 30°→Note:- Please don't give any unnecessary answer as well as wrong answer I request to all... and by the way it's a question of class 10's sample papers.

Answer»

ANSWER:

x=45

Step-by-step EXPLANATION:

SIN2X= sin45cos45+sin30

sin2x= 1/√2×1/√2+1/2

sin2x=1/2+1/2

sin2x=1

sin2x=sin90

2x=90

x=45

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Find the value of x in the equation sin2x = sin 45° cos 45°+ sin 30°→Note:- Please don't give any unnecessary answer as well as wrong answer I request to all... and by the way it's a question of class 10's sample papers.​​​

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Find the value of x in the equation sin2x = sin 45° cos 45°+ sin 30°→Note:- Please don't give any unnecessary answer as well as wrong answer I request to all... and by the way it's a question of class 10's sample papers.