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Find the value of X if : √X /x-1 + √1-x/ x=13/6 |
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Answer» ANSWER: Let x1−x−−−√x1−x = y. Then, the given equation reduces to y + 1y=1361y=136 ⇒ 6 (y2 + 1) = 13 y ⇒ 6Y2 – 13y + 6 = 0 ⇒ 6y2 – 9y – 4y + 6 = 0 ⇒ 3y (2Y – 3) – 2(2y – 3) = 0 ⇒ (3y – 2) (2y – 3) = 0 ⇒ y = 2323 and 3232 when y = 2323, x1−x−−−√x1−x = 2323 ⇒ x1−xx1−x = 4949 ⇒ 9x = 4 – 4X ⇒ 13x = 4 ⇒ x = 413413 when y = 3232, x1−x−−−√x1−x = 3232 ⇒ x1−xx1−x = 9494 ⇒ 4x = 9 – 9x ⇒ 13x = 9 ⇒ x = 913.Read more on Sarthaks.com - https://www.sarthaks.com/999204/what-is-one-of-the-values-of-x-in-the-equation-x-1-x-1-x-x-13-6?show=999219#a999219 |
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