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Find the value of x if p+7=0,q-12=0,and x²+px+q=0​

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\large \green {\underline{answer}} \\ \\ \large \implies{x \: = 3 \: \: and \: \: x = 4} \\ \\ \large \implies \orange {\underline{find}} \\ \\ \large \implies{values \: \: of \: \: x} \\ \\ \large \implies \green{ \underline{step - \: by \: - \: step \: \: explanation}} \\ \\ \large \implies \pink{ \underline{given}} \\ \\ \large \implies{p + 7 = 0} \\ \\ \large \implies{q - 12 = 0} \\ \\ \large \implies{equation \: = {x}^{2} + px + q = 0 } \\ \\ \large \implies{put \: \: the \: \: value \: \: of \: \: p \: \: and \: \: q \: \: in \: \: above \: \: equations} \\ \\ \large \implies{ {x}^{2} - 7x + 12 = 0 } \\ \\ \large \implies{ {x}^{2} - 4x - 3x + 12 = 0 } \\ \\ \large \implies{x(x - 4) - 3(x - 4) = 0} \\ \\ \large \implies{(x - 3)(x - 4) = 0} \\ \\ \large \implies \therefore \green{ \boxed{x = 3 \: \: \: \: and \: \: \: x = 4 }}


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