1.

Find the value of x for which 2x ,(x+10) and (3x+2) are three consecutive terms of an AP.​

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Answer:

as the terms 2x ,(x+10) ,(3X+2) are THREE consecutive terms of an AP

so, the common DIFFERENCE is equal

(x+10)-2x=(3x+2)-(x+10)

=> x+10-2x=3x+2-x-10

=> -x+10=2x-8

=> -x-2x= -8-10

=> -3x= -18

=> x = -18/-3=6

=> x=6


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