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Find the value of θ in each of the following. (θ is an acute angle.) (i) sec 2θ = 2 √3 (ii) 4 cot 3θ - 4 = 0 (iii) 3 tan2 θ + 2 = 3 |
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Answer» Find the VALUE of θ in each of the following. (θ is an ACUTE angle.) (i) SEC 2θ = 2/√3 (ii) 4 COT 3θ - 4 = 0 (iii) 3 tan² θ + 2 = 3 [correct question] Given: (i) sec 2θ = 2/√3 (ii) 4 cot 3θ - 4 = 0 (iii) 3 tan² θ + 2 = 3 To find: The value of the θ. Solution: (i) sec 2θ = 2/√3 sec 2θ = sec 30° 2θ = 30° θ = 15°(ii) 4 cot 3θ - 4 = 0 4 cot 3θ = 4 cot 3θ = 1 cot 3θ = cot 45° 3θ = 45° θ = 15°(iii) 3 tan² θ + 2 = 3 3 tan² θ = 3-2 3 tan² θ =1 tan² θ = 1/3 tanθ = √1/3 tanθ = 1/√3 tanθ = tan 30° θ = 30° |
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