1.

Find the value of `sin^(-1)(sin.(5pi)/3)`.

Answer» Since `(5pi)/3 cancelin[-pi/2,pi/2]`
`:.sin^(-1)(sin(5pi)/3)`
`=sin^(-1)(sin(2x-pi/3))`
`sin^(-1)(-sin.(pi)/3)`
`sin^(-1)(sin.(-pi/3))`
`=-pi/3`


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