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Find the value of `sin^(-1)(sin.(5pi)/3)`. |
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Answer» Since `(5pi)/3 cancelin[-pi/2,pi/2]` `:.sin^(-1)(sin(5pi)/3)` `=sin^(-1)(sin(2x-pi/3))` `sin^(-1)(-sin.(pi)/3)` `sin^(-1)(sin.(-pi/3))` `=-pi/3` |
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