Find the value of polynomial p(x)=8x3-6x2-4x+3, when x=-1/2

1.	Find the value of polynomial p(x)=8x3-6x2-4x+3, when x=-1/2
Answer» p(x) = 8x³ - 6x² - 4x + 3 p\((-\frac{1}{2})\) = 8\((\frac{-1}{2})^3\) - 6\((\frac{-1}{2})^2\) - 4 x \(\frac{-1}{2}\) + 3 = \(8\times\frac{-1}{8}-6\times\frac{1}{4}+2+3\) = \(-1\frac{-3}{2}+5\) = \(4\,\frac{-3}{2}=\frac{8-3}{2}=\frac{5}{2}\)

Answer»

p(x) = 8x³ - 6x² - 4x + 3

p\((-\frac{1}{2})\) = 8\((\frac{-1}{2})^3\) - 6\((\frac{-1}{2})^2\) - 4 x \(\frac{-1}{2}\) + 3

= \(8\times\frac{-1}{8}-6\times\frac{1}{4}+2+3\)

= \(-1\frac{-3}{2}+5\)

= \(4\,\frac{-3}{2}=\frac{8-3}{2}=\frac{5}{2}\)

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Find the value of polynomial p(x)=8x3-6x2-4x+3, when x=-1/2

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