1.

Find the value of p in each of the following.....​

Answer»

<P>ANSWER: (a) 3/2 (B) 7

Step-by-step EXPLANATION:

(a) 7^{2p} \div 343 = 1

\dfrac{7^{2p} }{343} = 1

\dfrac{7^{2p} }{7^{3} } = 1

7^{2p-3} = 1

7^{2p-3} = 7^{0}

2p - 3 =0

2p = 3\\

p = \dfrac{3}{2}

∴ p = 3/2

(b) (3^{p})^{3} \times 9^{2} \times 243^{-5} = 1

(3^{p})^{3} \times (3^{2})^{2} \times (3^5)^{-5} = 1

3^{3p} \times 3^{4} \times 3^{-25} = 1

{3^{3p+4+(-25)} = 1

{3^{3p+4-25} = 1

{3^{3p-21} = 1

3^{3p-21} = 3^0

3p-21 = 0

3p = 21

p = \dfrac{21}{3}

p = 7

∴ p = 7



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