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Find the value of p, if (x-2) is a factor of a polynomial x^3-px^2+12 |
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Answer» Answer: p=5 Step-by-step explanation: ifx-2=0 x=2 x³-px²+12=0 putting the VALUE of x 2³-p2²+12=0 8-4p+12=0 -4p+20=0 -4p=-20 p=-20/-4 p=5 follow me PLEASE mark it as the BRAINLIEST |
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