Find the value of p, if log cos 60° sin30° = p.1. 42. 23. 34. 1

1.	Find the value of p, if log cos 60° sin30° = p.1. 42. 23. 34. 1
Answer» Correct Answer - Option 4 : 1 CONCEPT: As we know that \(\operatorname{Sin} {30^ \circ } = \frac{1}{2}\) and \(\operatorname{cos} {60^ \circ } = \frac{1}{2}\). log _x (x) = 1 CALCULATION: Given log cos 60° sin30° = p On putting \(\operatorname{Sin} {30^ \circ } = \frac{1}{2}\) and \(\operatorname{cos} {60^ \circ } = \frac{1}{2}\) we get, \( ⇒ {\log _{\frac{1}{2}}}\frac{1}{2} = p\) ⇒ p = 1 Therefore, option (d) is the correct answer.

Answer» Correct Answer - Option 4 : 1

CONCEPT:

As we know that \(\operatorname{Sin} {30^ \circ } = \frac{1}{2}\) and \(\operatorname{cos} {60^ \circ } = \frac{1}{2}\).
log _x (x) = 1

CALCULATION:

Given log cos 60° sin30° = p

On putting \(\operatorname{Sin} {30^ \circ } = \frac{1}{2}\) and \(\operatorname{cos} {60^ \circ } = \frac{1}{2}\) we get,
\( ⇒ {\log _{\frac{1}{2}}}\frac{1}{2} = p\)

⇒ p = 1

Therefore, option (d) is the correct answer.

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Find the value of p, if log cos 60° sin30° = p.1. 42. 23. 34. 1

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