find the value of p for which the root of the equation px(x-2)+6=0 ,ar

1.	find the value of p for which the root of the equation px(x-2)+6=0 ,are equal
Answer» then just solve the equation and then make it in the form of ax2 +bx + cthen by the formula of ✓b2-4ac =0find the value of pgot it??? Px2-2px+6=0 b2-4ac=0(given) (-2px)2-4(px2)(6)=0 4p2x2-4(6px2)=0 4p2x2-24px2=0 4p2x2=24px2 P2=24px2/4x2 p2=6p p=6p/p p=6

find the value of p for which the root of the equation px(x-2)+6=0 ,are equal

Answer»

then just solve the equation and then make it in the form of ax2 +bx + cthen by the formula of ✓b2-4ac =0find the value of pgot it???

Px2-2px+6=0

b2-4ac=0(given)

(-2px)2-4(px2)(6)=0

4p2x2-4(6px2)=0

4p2x2-24px2=0

4p2x2=24px2

P2=24px2/4x2

p2=6p

p=6p/p

p=6