Find the value of p for which (3/5)^p(5/3)^2p=125/27

1.	Find the value of p for which (3/5)^p(5/3)^2p=125/27
Answer» $hy\\friend$ ⇒(3/5)^X × (5/3)^2x. = 125/27 So ⇒(5/3)^{-x} × (5/3)^2x =125/27 Further simplifying the expression (5/3)^x =125/27 (5/3)^x =(5/3)^3 So from here CLEARLY x = 3 $thankyou\\brainly user$

Answer»

$hy\\friend$

⇒(3/5)^X × (5/3)^2x.

= 125/27

⇒(5/3)^{-x} × (5/3)^2x

=125/27

Further simplifying the expression

(5/3)^x =125/27

(5/3)^x =(5/3)^3

So from here CLEARLY x = 3

$thankyou\\brainly user$

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Find the value of p for which (3/5)^p(5/3)^2p=125/27

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