1.

Find the value of m for which the roots of the quadratic equation mx(6x+10)+25=0, are equal

Answer»

mx(6x+10)+25=0
6mx2 +10mx+25=0
Roots are equal so D=0
{10m}2 −4.25(6m)=0
m2 −6m=0
m(m−6)=0
∴m=6



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