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Find the value of log5 V625. |
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Answer» log5(sqrt[625]) Rewrite as anequation. log5(sqrt[625]) = x Rewritelog5(sqrt[625] )=xin exponential form using the definition of a logarithm. Ifx andb are positive real numbers andb does not equal1, thenlogb(x)=y isequivalenttob^y=x 5^x = 25 Createequivalentexpressionsin theequationthat all have equalbases. 5^x = 5^2 Since thebasesare the same, the twoexpressionsare only equal if theexponentsare also equal. x = 2 Thevariablex is equal to 2 2 log .base 5 and 5 square ,it's ans are 2 |
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