1.

Find the value of k when the root of the quadratic equationx² + k(4x+k-1)+ 2= 0 are real and equal.​

Answer»

ANSWER:

Answer: K=-1 or 2/3

Step-by-step explanation:

x^2 + k(4x+k-1)+2

= x^2 + 4KX + (k^2-k+2)

When the ROOTS are EQUAL b^2=4ac

So (4k)^2=4*1*(k^2-k+2)

16k^2=4k^2-4k+8

12k^2+4k-8=0

3k^2+k-2=0

(3k-2)(k+1)=0

So k=2/3 or -1

So the polynomial is x^2-4x+4=(x-2)^2

Or

x^2+8x/3+16/9=(x+4/3)^2

Step-by-step explanation:


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