1.

find the value of k so that the quadratic equation 3 X square + 2 k x + 27 is equal to zero has real and equal roots...​

Answer»

ANSWER:

k = 9

Step-by-step EXPLANATION:

3 {x}^{2}  + 2kx + 27

if \: the \: equation \: has \: real \: andequal\: roots \: it \: should \: satisfy

{b}^{2}  - 4ac = 0

{(2k)}^{2}  - 4(3)(27) = 0

4 {k}^{2}  - 324=0

4 {k}^{2}  = 324

{k}^{2}  = 81

k = 9

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