1.

Find the value of k so that the lines 2x-3y=9 and kx-9y=18 will be parallel

Answer»

\huge \boxed{ \underline{ \underline{ \bf{Answer}}}}

TO FIND :- The VALUE of k.

Its Given :- Lines are parallel.

2x - 3y = 9

kx - 9Y = 18

For Intersecting lines :- a₁/a₂ ≠ b₁/b₂. ( UNIQUE solution )

For coincident lines :- a₁/a₂ = b₁/b₂ = c₁/c₂. ( Infinite solution )

For Parallel lines :- a₁/a₂ = b₁/b₂ ≠ c₁/c₂. ( No solution )

2x - 3y -9 = 0

kx - 9y -18 = 0

a₁ = 2  , b₁ = -3   ,  c₁ = -9

a₂ = k  , b₂ = -9  ,  c₂ = -18

a₁/a₂ = b₁/b₂ ≠ c₁/c₂

2/k = 3/9 ≠ 9/18

3k = 18

k = 18/3

k = 6.

Hence, the value of "k" = 6.


Discussion

No Comment Found

Related InterviewSolutions